Prealgebra · Lesson 1.4

Checkpoint Problems

Solve this lesson, free →All lessons

The last three lessons gave you three tools. You can reorder and pair sums, handle signs, and multiply using the distributive property. The problems below are unlabelled, so nothing tells you which tool a problem needs, and several need two at once. Read slowly, look for structure first, and expect to solve each one without paper.

Problem
For 14 days, a bakery celebrates its birthday. On day 1 it gives away 1 free roll, on day 2 it gives 2, and so on up to 14 rolls on day 14, and it runs the same giveaway at each of its 5 branches. How many rolls does the whole chain give away?
Show a hint
  • First find one branch’s total: pair 1+14, 2+13, …, the trick you learned from a seven-year-old.
Show the full solution
Pair the days, 1+14,2+13,,7+8, into seven 15s, so 7×15=105 rolls per branch. Then 5×105=525.
Problem
Zoe rings up six items on Monday costing 41,52,63,74,85,96. On Tuesday she rings up 39,50,61,72,83,94. Without finding either total, work out how much more Monday’s bill is than Tuesday’s.
Show the full solution
Match the lists item by item. Every Monday item costs 2 more, and there are six items, so Monday’s bill is 6×2=12 more. Neither total was needed.
Problem
A freight scale reports that crate A outweighs crate B by 9 kg, that is, AB=9. The mover wants the comparison the other way around. What is BA?
Show the full solution
BA=(AB)=9. Reversing a subtraction gives the opposite of the original difference.
Problem
Here is a puzzle. Split the numbers 3,5,8,0 into two pairs, multiply inside each pair, then add the two results. What is the largest total you can reach?
Show a hint
  • Whatever number 0 is paired with vanishes from the final total. Which number can you best afford to lose?
Show the full solution
Pair 0 with 3, so the other pair is 5×8=40 and the total is 40+0=40. Anything paired with 0 drops out of the total, so spend the 0 on the smallest number. The other pairings give only 15 and 24.
Problem
Compute (445(4×111))×777.
Show a hint
  • Work out the inner parentheses first: what is 4×111?
Show the full solution
Inside, 4×111=444, so the parentheses hold 445444=1, and the whole expression is 1×777=777. A big expression can hide a factor of 1.
Problem
Twins Ria and Kio race through a worksheet. Ria computes 46×45, and Kio computes 46×44+46. Their teacher asks for Ria’s answer minus Kio’s. Find it the lazy way.
Show the full solution
Kio’s 46×44+46 is forty-four 46s plus one more, which is forty-five 46s, exactly Ria’s 46×45. The two are equal, so their difference is 0.
Problem
A frog sits at 0 on a number line. It makes 8 jumps of +5, then 6 jumps of 7. Where does the frog land?
Show the full solution
The jumps are two products, 8×5=40 forward, then 6×(7)=42 back. The frog lands at 40+(42)=2.
Problem
Compute 18×7+18×21+18×12.
Show the full solution
All three products share the 18, so factor it out. 18×(7+21+12)=18×40=720.
Problem
Compute (294+295+296++306)(13×294).
Show a hint
  • Every number in the run is 294 carrying a little extra, 294+0, 294+1, …, 294+12.
  • Subtracting 13×294 strips one 294 out of every term. What extras are left behind?
Show the full solution
Each number from 294 to 306 is 294 plus a small excess, 294+0,294+1,,294+12. Subtracting 13×294 strips the 294 from every term, leaving 1+2++12, which pairs into six 13s for 78.
Problem
Two siblings argue. Asha says 399×501 and 400×500 must be equal, “because you just move a 1 from one number to the other.” Settle it. Compute the larger minus the smaller.
Show a hint
  • Both products have 399×500 hiding inside.
  • 399×501=399×500+399, while 400×500=399×500+500.
Show the full solution
Peel a layer off each, 399×501=399×500+399 and 400×500=399×500+500. They share the same bulk, so 400×500 is larger by 500399=101.
Problem
Compute 64×3663×35 without long multiplication. (Careful, no factor is shared… yet.)
Show a hint
  • Manufacture a shared factor: rewrite 64 as 63+1.
  • Then 64×36=63×36+36, and now two of the products share a 63.
  • 63×3663×35 collapses. Add back the spare 36.
Show the full solution
Write 64×36=(63+1)×36=63×36+36. Then 63×36+3663×35=63×(3635)+36=63+36=99. When no shared factor exists, build one.

If any of those three still feels wobbly, revisit its lesson before moving on. Up next is the last of the four operations, division, and it will fall to the same playbook.