Prealgebra · Lesson 11.10

Families of Quadrilaterals

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Four-sided shapes are sorted into families by shared traits like parallel sides, equal sides, and right angles. Every member of a family has all of that family's properties, so once you know a shape is a parallelogram, every parallelogram rule applies to it. We start with a frame of four rods bolted loosely at the corners.

Problem
8585
A picture frame is built from two 8 inch rods and two 5 inch rods, hinged loosely at the corners. Push on one corner and the rectangle leans into the slanted shape above, then leans further with another push. The angles keep changing. What is the perimeter of the leaning shape, in inches?
Show a hint
  • Leaning the frame does not change the rods, only the angles at the hinges.
  • Add up the four rod lengths, 8+5+8+5.
Show the full solution
Add up the four rod lengths. 8+5+8+5=26 inches. Leaning the frame changes the angles at the hinges, never the rods, so every position has this same perimeter.
Problem
In one leaning position, the hinge at the bottom left of the frame reads 70 degrees. The bottom rod and the top rod stay parallel, and so do the two side rods. Using what you know about parallel lines, how many degrees is the angle at the bottom right hinge?
Show a hint
  • The two side rods are parallel, and the bottom rod crosses both of them, so the two bottom angles are co-interior angles.
  • Co-interior angles between parallel lines add to 180 degrees.
Show the full solution
The two bottom hinge angles add to 180 degrees, so the right one is 18070=110 degrees. The bottom rod crosses both parallel side rods, which is what makes those two angles co-interior.
Problem
A parallelogram-shaped stencil has a base of 10 cm, slanted sides of 7 cm, and a height of 6 cm measured straight up from the base. Snip the overhanging triangle off one end and slide it across to plug the gap at the other end. The pieces form a rectangle. What is the stencil's area in square centimeters?
Show a hint
  • The rectangle you build has the same base and the same height as the stencil.
  • A 10 by 6 rectangle has area 10×6.
Show the full solution
The rectangle is 10 by 6, so the area is 10×6=60 square centimeters. The snipped triangle fills the gap exactly, so nothing is gained or lost, and the 7 cm slant never enters the calculation.
Problem
A solar panel shaped like a parallelogram has sides of 12 m and 5 m. The perpendicular distance between its two 12 m edges is 4 m. An installer multiplies 12×5=60 and quotes the area as 60 square meters. What is the actual area, in square meters?
Show a hint
  • Area needs the base times the height, and the height is the perpendicular distance, not the slanted side.
  • The base is 12 and the height is 4.
Show the full solution
Area is base times height, 12×4=48 square meters. The 5 m side is slanted, so it is longer than the true height of 4 m, and using it overquotes by 12 square meters.
Problem
129
A club logo is drawn by marking a horizontal segment of length 12 and a vertical segment of length 9 that cross at each other's midpoints, then connecting the four endpoints. The result is the rhombus above, a quadrilateral with four equal sides. It sits inside a dashed 12 by 9 rectangle, and in each quarter of that rectangle the logo covers exactly half. What is the area of the logo?
Show a hint
  • The dashed rectangle has area 12×9=108.
  • Each quarter-rectangle is cut along its diagonal, so the logo takes exactly half of the whole rectangle.
Show the full solution
The logo covers half the dashed rectangle, and 12×9=108, so the area is 54. Each quarter of the rectangle is cut along its diagonal, which is why the logo takes exactly half.
Problem
A rhombus-shaped garden plot has an area of 40 square feet. One diagonal measures 10 feet. Using the pattern you just discovered, how many feet long is the other diagonal?
Show a hint
  • A rhombus fills half its bounding rectangle, so area = (diagonal × diagonal) ÷2.
  • Solve 10×d÷2=40.
Show the full solution
The diagonals multiply to twice the area, 10×d=80, so d=8 feet.
Problem
A highway warning sign is a rhombus with diagonals of 12 inches and 16 inches. The diagonals cross at right angles at their midpoints, cutting the sign into four identical right triangles. Use one of those triangles and the Pythagorean Theorem to find the side length of the sign, in inches.
Show a hint
  • Each right triangle has legs equal to half of each diagonal, 6 and 8.
  • Find the hypotenuse of a 6-8 right triangle.
Show the full solution
Half-diagonals of 6 and 8 form the legs, and the sign's side is the hypotenuse. Since 62+82=36+64=100, the side is 100=10 inches.
Problem
A square napkin is folded once along its diagonal, and the crease measures 10 inches. A square is a rhombus whose diagonals are equal, so both diagonals of the napkin are 10. What is the napkin's area in square inches?
Show a hint
  • Use the rhombus area tool with d1=d2=10.
  • Half of 10×10.
Show the full solution
With equal diagonals of 10, the rhombus tool gives 12×10×10=50 square inches. You met this napkin in the last lesson, where the side came out to 102, and squaring that side gives the same 50.
Problem
1154
A kitchen backsplash uses trapezoid tiles with parallel edges of 5 inches and 11 inches, set 4 inches apart. Tiles snap together in pairs, one flipped upside down as shown, forming a parallelogram. What is the area of that two-tile parallelogram, in square inches?
Show a hint
  • The flipped tile lays its 5 inch edge alongside the other tile's 11 inch edge, so the parallelogram's base is 5+11.
  • Base 16, height 4, area =16×4.
Show the full solution
Snapped together, the pair forms a parallelogram with base 5+11=16 and the same 4 inch height, so the area is 16×4=64 square inches.
Problem
One single tile is half of that two-tile parallelogram. Check the shortcut on a bigger tile. A trapezoid window has parallel edges of 9 feet and 13 feet, set 6 feet apart. What is its area in square feet?
Show a hint
  • Two copies would form a parallelogram of base 9+13=22 and height 6, and the window is half of it.
  • Compute 12×22×6.
Show the full solution
Doubling the window gives a parallelogram of area 22×6=132, and one window is half of that, 12×132=66 square feet. In one line, area =12(9+13)(6).

Practice these ideas

Practice
Here are four claims. (a) Every square is a rhombus. (b) Every rhombus is a square. (c) Every rectangle is a parallelogram. (d) A quadrilateral can have exactly three right angles. How many of the four claims are true?
Show the solution
(a) is true, a square's four equal sides make it a rhombus. (b) is false, a leaning rhombus has no right angles. (c) is true, right angles do not remove parallel sides. (d) is false, three right angles use up 270 degrees and the fourth must be 90, giving four right angles, never exactly three. That makes 2 true claims.
Practice
One angle of a parallelogram measures 48 degrees. How many degrees is the largest angle of the parallelogram?
Show the solution
A neighbor of the 48 degree angle measures 18048=132 degrees, and opposite angles repeat the pair. The largest is 132.
Practice
A rhombus has a perimeter of 52 cm, and one of its diagonals measures 24 cm. Use the four right triangles inside the rhombus to find the length of the other diagonal, in centimeters.
Show the solution
Each side is 52÷4=13, and the half-diagonals are the legs of a right triangle with hypotenuse 13. One leg is 24÷2=12, so the other satisfies a2+122=132, giving a2=169144=25 and a=5. The full diagonal is 2×5=10 cm.
Practice
A stained-glass pane is a rhombus with diagonals of 14 inches and 6 inches. What is its area in square inches?
Show the solution
Half the product of the diagonals is 12×14×6=42 square inches.
Practice
A square coaster has a diagonal of 6 inches. What is its area in square inches?
Show the solution
Treat the square as a rhombus with equal diagonals. Its area is 12×6×6=18 square inches, no side length needed.
Practice
A parallelogram-shaped field has an area of 91 square meters and a base of 13 meters. What is its height, in meters?
Show the solution
Height =91÷13=7 meters.
Practice
The cross-section of a drainage channel is a trapezoid with parallel edges of 4 feet and 10 feet, set 5 feet apart. What is the area of the cross-section in square feet?
Show the solution
The average base is 4+102=7, and 7×5=35 square feet.
Practice
A trapezoid banner has an area of 60 square inches, a height of 6 inches, and one base of 7 inches. How many inches long is the other base?
Show the solution
The sum of the bases is 2×606=20, so the other base is 207=13 inches.
Practice
A pixel-art gem on a screen has corners at (0,4), (6,0), (12,4), and (6,8). Its diagonals are the horizontal segment from (0,4) to (12,4) and the vertical segment from (6,0) to (6,8). What is the gem's area in square pixels?
Show the solution
The diagonals measure 12 and 8, cross at (6,4), and are perpendicular, so the area is 12×12×8=48 square pixels.
Practice
A tile has four 6 cm sides and at least one right angle. Explain to yourself which family the tile must belong to, then find its area in square centimeters.
Show the solution
Four equal sides make the tile a rhombus, hence a parallelogram. One 90 degree angle forces each neighbor to 18090=90, so all four angles are right and the tile is a square. Its area is 62=36 square centimeters.